Q2Long answerExercise 11.3
2 AM 1 Now, = sin 45° = OA 2 So, AM = 10 × cm. Therefore, A B = 10 2 cm and OM = OA cos 45° = 10× cm = 5 2 cm So, area of ∆ OAB = base × height
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(16π – 32 ) cm2
2 AM 1 Now, = sin 45° = OA 2 So, AM = 10 × cm. Therefore, A B = 10 2 cm and OM = OA cos 45° = 10× cm = 5 2 cm So, area of ∆ OAB = base × height
(16π – 32 ) cm2