Q2Long answerExercise 11.3
2 By Heron’s Formula, ar (ABC) = s(s–a ) (s–b ) (s–c) = 56 × 8 × 6 × 42 cm = 336 cm So, area of the shaded region = area of the ∆ ABC – area of the three sectors 2 2 = (336 – 39.25) cm = 296.75 cm Alternate Method for ar (ABC) 2 2 2 2 2 2 Here, AB + BC = (14) + (48) = 2500 = (50) = (CA) So, ∠B = 90° (By converse of Pythagoras Theorem)
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(16π – 32 ) cm2