Chapter 4 – Chemical Bonding and Molecular Structure

Class 11 Chemistry · 68 questions · 33 with answers

Questions

Q1Multiple choice

Isostructural species are those which have the same shape and hybridisation. Among the given species identify the isostructural pairs.

  • (i)[NF3 and BF3] – +
  • (ii)[BF4 and NH4 ]
  • (iii)[BCl3 and BrCl3] –
  • (iv)[NH3 and NO3 ]
Show answer

(ii) [BF4 and NH4 ]

Q2Multiple choice

Polarity in a molecule and hence the dipole moment depends primarily on electronegativity of the constituent atoms and shape of a molecule. Which of the following has the highest dipole moment?

  • (i)CO2
  • (ii)HI
  • (iii)H2O
  • (iv)SO2 + – +
Show answer

(iii) H2O

Q3Multiple choice

The types of hybrid orbitals of nitrogen in NO2 , NO3 and NH4 respectively are expected to be

  • (i)sp, sp3 and sp2
  • (ii)sp, sp2 and sp3
  • (iii)sp2, sp and sp3
  • (iv)sp2, sp3 and sp
Show answer

(ii) sp, sp2 and sp3

Q4Multiple choice

Hydrogen bonds are formed in many compounds e.g., H2O, HF, NH3 . The boiling point of such compounds depends to a large extent on the strength of hydrogen bond and the number of hydrogen bonds. The correct decreasing order of the boiling points of above compounds is :

  • (i)HF > H2O > NH3
  • (ii)H2O > HF > NH3
  • (iii)NH3 > HF > H2O
  • (iv)NH3 > H2O > HF 3–
Show answer

(ii) H2O > HF > NH3

Q5Multiple choice

In PO4 ion the formal charge on the oxygen atom of P–O bond is

  • (i)+1
  • (ii)–1
  • (iii)– 0.75
  • (iv)+ 0.75 –
Show answer

(ii) –1

Q6Multiple choice

In NO3 ion, the number of bond pairs and lone pairs of electrons on nitrogen atom are

  • (i)2, 2
  • (ii)3, 1
  • (iii)1, 3
  • (iv)4, 0
Show answer

(iv) 4, 0

Q7Multiple choice

Which of the following species has tetrahedral geometry? –

  • (i)BH4 –
  • (ii)NH2 2–
  • (iii)CO3 +
  • (iv)H3O
Show answer

(i) BH4 –

Q8Multiple choice

Number of π bonds and σ bonds in the following structure is–

  • (i)6, 19
  • (ii)4, 20
  • (iii)5, 19
  • (iv)5, 20
Show answer

(iii) 5, 19

Q9Multiple choice

Which molecule/ion out of the following does not contain unpaired electrons? +

  • (i)N2
  • (ii)O2 2–
  • (iii)O2
  • (iv)B2
Show answer

(iii) O2

Q10Multiple choice

In which of the following molecule/ion all the bonds are not equal?

  • (i)XeF4 –
  • (ii)BF4
  • (iii)C2H4
  • (iv)SiF4
Show answer

(iii) C2H4

Q11Multiple choice

In which of the following substances will hydrogen bond be strongest?

  • (i)HCl
  • (ii)H2O
  • (iii)HI
  • (iv)H2S
Show answer

(ii) H2O

Q12Multiple choice

If the electronic configuration of an element is 1s2 2s2 2p6 3s2 3p6 3d2 4s2, the four electrons involved in chemical bond formation will be_____.

  • (i)3p6
  • (ii)3p6, 4s2
  • (iii)3p6, 3d2
  • (iv)3d2, 4s2
Show answer

(iv) 3d2, 4s2

Q13Multiple choice

Which of the following angle corresponds to sp2 hybridisation?

  • (i)90°
  • (ii)120°
  • (iii)180°
  • (iv)109° The electronic configurations of three elements, A, B and C are given below. Answer the questions 14 to 17 on the basis of these configurations. A 1s2 2s2 2p6 B 1s2 2s2 2p6 3s2 3p3 C 1s2 2s2 2p6 3s2 3p5
Show answer

(ii) 120°

Q14Multiple choice

Stable form of A may be represented by the formula :

  • (i)A
  • (ii)A2
  • (iii)A3
  • (iv)A4
Show answer

(i) A

Q15Multiple choice

Stable form of C may be represented by the formula :

  • (i)C
  • (ii)C2 41 Chemical Bonding and Molecular Structure
  • (iii)C3
  • (iv)C4
Show answer

(ii) C2 41 Chemical Bonding and Molecular Structure

Q16Multiple choice

The molecular formula of the compound formed from B and C will be

  • (i)BC
  • (ii)B2C
  • (iii)BC2
  • (iv)BC3
Show answer

(iv) BC3

Q17Multiple choice

The bond between B and C will be

  • (i)Ionic
  • (ii)Covalent
  • (iii)Hydrogen
  • (iv)Coordinate
Show answer

(ii) Covalent

Q18Multiple choice

Which of the following order of energies of molecular orbitals of N2 is correct?

  • (i)(π2py ) < (σ2pz) < (π*2px) ≈ (π*2py )
  • (ii)(π2py ) > (σ2pz) > (π*2px) ≈ (π*2py )
  • (iii)(π2py ) < (σ2pz) > (π*2px) ≈ (π*2py )
  • (iv)(π2py ) > (σ2pz) < (π*2px) ≈ (π*2py )
Show answer

(i) (π2py ) < (σ2pz) < (π*2px) ≈ (π*2py )

Q19Multiple choice

Which of the following statement is not correct from the view point of molecular orbital theory?

  • (i)Be2 is not a stable molecule. +
  • (ii)He2 is not stable but He2 is expected to exist.
  • (iii)Bond strength of N2 is maximum amongst the homonuclear diatomic molecules belonging to the second period.
  • (iv)The order of energies of molecular orbitals in N2 molecule is σ2s < σ* 2s < σ2pz < (π2px = π2py ) < (π* 2px = π* 2py) < σ*2pz
Show answer

(iv) The order of energies of molecular orbitals in N2 molecule is σ2s < σ* 2s < σ2pz < (π2px = π2py ) < (π* 2px = π* 2py) < σ*2pz

Q20Multiple choice

Which of the following options represents the correct bond order : – +

  • (i)O2 > O2 > O2 – +
  • (ii)O2 < O2 < O2 – +
  • (iii)O2 > O2 < O2 – +
  • (iv)O2 < O2 > O2
Show answer

(ii) O2 < O2 < O2 – +

Q21Multiple choice

The electronic configuration of the outer most shell of the most electronegative element is

  • (i)2s22p5
  • (ii)3s23p5
  • (iii)4s24p5
  • (iv)5s25p5
Show answer

(i) 2s22p5

Q22Multiple choice

Amongst the following elements whose electronic configurations are given below, the one having the highest ionisation enthalpy is

  • (i)[Ne]3s23p1
  • (ii)[Ne]3s23p3
  • (iii)[Ne]3s23p2
  • (iv)[Ar]3d104s24p3
Show answer

(ii) [Ne]3s23p3

Q23Multiple correct

Which of the following have identical bond order? –

  • (i)CN +
  • (ii)NO –
  • (iii)O2 2–
  • (iv)O2
Show answer

(i) CN +

(ii) NO –

Q24Multiple correct

Which of the following attain the linear structure:

  • (i)BeCl2
  • (ii)NCO+
  • (iii)NO2
  • (iv)CS2
Show answer

(i) BeCl2

(iv) CS2

Q25Multiple correct

CO is isoelectronic with +

  • (i)NO
  • (ii)N2
  • (iii)SnCl2 –
  • (iv)NO2
Show answer

(i) NO

(ii) N2

Q26Multiple correct

Which of the following species have the same shape?

  • (i)CO2
  • (ii)CCl4
  • (iii)O3 –
  • (iv)NO2 2–
Show answer

(iii) O3 –

(iv) NO2 2–

Q27Multiple correct

Which of the following statements are correct about CO3 ?

  • (i)The hybridisation of central atom is sp3.
  • (ii)Its resonance structure has one C–O single bond and two C=O double bonds.
  • (iii)The average formal charge on each oxygen atom is 0.67 units.
  • (iv)All C–O bond lengths are equal. 43 Chemical Bonding and Molecular Structure
Show answer

(iii) The average formal charge on each oxygen atom is 0.67 units.

(iv) All C–O bond lengths are equal. 43 Chemical Bonding and Molecular Structure

Q28Multiple correct

Dimagnetic species are those which contain no unpaired electrons. Which among the following are dimagnetic?

  • (i)N2 2–
  • (ii)N2
  • (iii)O2 2–
  • (iv)O2
Show answer

(i) N2 2–

(iv) O2

Q29Multiple correct

Species having same bond order are :

  • (i)N2 –
  • (ii)N2 +
  • (iii)F2 –
  • (iv)O2
Show answer

(iii) F2 –

(iv) O2

Q30Multiple correct

Which of the following statements are not correct?

  • (i)NaCl being an ionic compound is a good conductor of electricity in the solid state.
  • (ii)In canonical structures there is a difference in the arrangement of atoms.
  • (iii)Hybrid orbitals form stronger bonds than pure orbitals.
  • (iv)VSEPR Theory can explain the square planar geometry of XeF4.
Show answer

(i) NaCl being an ionic compound is a good conductor of electricity in the solid state.

(ii) In canonical structures there is a difference in the arrangement of atoms.

Q31Short answer

Explain the non linear shape of H2S and non planar shape of PCl3 using valence shell electron pair repulsion theory.

Q32Short answer

Using molecular orbital theory, compare the bond energy and magnetic + – character of O2 and O2 species.

Show answer

(i) According to molecular orbital theory electronic configurations of + – O2 and O2 species are as follows : O2 : (1s) (* 1s ) (2s) (* 2s ) (2pz) (2px2 , 2p2y ) (* 2px1 ) + 2 2 2 2 2 O2 : (1s) (* 1s ) (2s) (* 2s ) (2pz) (2p2x ,2p2y ) (* 2px2 , * 2py1) – 2 2 2 2 2 + 10 − 5 5 Bond order of O2 = = = 2.5 2 2 10 − 7 3 – Bond order of O2 = = = 1.5 2 2 + – Higher bond order of O2 shows that it is more stable than O2 . Both the species have unpaired electrons. So both are paramagnetic in nature.

Q33Short answer

Explain the shape of BrF5.

Q34Multiple choice

Structures of molecules of two compounds are given below :

  • (a)Which of the two compounds will have intermolecular hydrogen bonding and which compound is expected to show intramolecular hydrogen bonding.
  • (b)The melting point of a compound depends on, among other things, the extent of hydrogen bonding. On this basis explain which of the above two compounds will show higher melting point.
  • (c)Solubility of compounds in water depends on power to form hydrogen bonds with water. Which of the above compounds will form hydrogen bond with water easily and be more soluble in it.
Show answer

(a) Which of the two compounds will have intermolecular hydrogen bonding and which compound is expected to show intramolecular hydrogen bonding.

(b) The melting point of a compound depends on, among other things, the extent of hydrogen bonding. On this basis explain which of the above two compounds will show higher melting point.

(c) Solubility of compounds in water depends on power to form hydrogen bonds with water. Which of the above compounds will form hydrogen bond with water easily and be more soluble in it.

Q35Short answer

Why does type of overlap given in the following figure not result in bond formation?

Q36Short answer

Explain why PCl5 is trigonal bipyramidal whereas IF5 is square pyramidal.

Q37Short answer

In both water and dimethyl ether (CH3 — Ο — CH3 ), oxygen atom is central atom, and has the same hybridisation, yet they have different bond angles. Which one has greater bond angle? Give reason.

Show answer

[Hint : Dimethyl ether will have larger bond angle. There will be more repulsion between bond pairs of CH3 groups attached in ether than between bond pairs of hydrogen atoms attached to oxygen in water. The carbon of CH3 in ether is attached to three hydrogen atoms through σ bonds and electron pairs of these bonds add to the electronic charge density on carbon atom. Hence, repulsion between two —CH3 groups will be more than that between two hydrogen atoms.] IV. Matching Type 52. (i) → (c) (ii) → (a) (iii) → (e) (iv) → (d) 53. (i) → (e) (ii) → (a) (iii) → (b) (iv) → (c) 54. (i) → (c) (ii) → (d) (iii) → (a) (iv) → (b) 55. (i) → (d) (ii) → (e) (iii) → (b) (iv) → (a) 56. (i) → (c) (ii) → (a) (iii) → (b) V. Assertion and Reason Type 57. (i) 58. (i) 59. (iv) 65. (i) 66. (ii) 67. (ii) 68. (iii)

Q38Short answer

Write Lewis structure of the following compounds and show formal charge on each atom. HNO3, NO2, H2SO4

Q39Short answer

The energy of 2pz molecular orbital is greater than 2px and 2py molecular orbitals in nitrogen molecule. Write the complete sequence of energy levels in the increasing order of energy in the molecule. Compare the relative stability and the magnetic behaviour of the following species : + – 2+ N2, N2 , N2 , N2

Q40Multiple choice

What is the effect of the following processes on the bond order in N2 and O2? N2 N2 + e– O2 O2 + e– + +

  • (i)
  • (ii)
Q41Multiple choice

Give reasons for the following :

  • (i)Covalent bonds are directional bonds while ionic bonds are non- directional.
  • (ii)Water molecule has bent structure whereas carbon dioxide molecule is linear.
  • (iii)Ethyne molecule is linear. 45 Chemical Bonding and Molecular Structure
Q42Short answer

What is an ionic bond? With two suitable examples explain the difference between an ionic and a covalent bond?

Q43Short answer

Arrange the following bonds in order of increasing ionic character giving reason. N—H, F—H, C—H and O—H 2–

Q44Short answer

Explain why CO3 ion cannot be represented by a single Lewis structure. How can it be best represented?

Q45Short answer

Predict the hybridisation of each carbon in the molecule of organic compound given below. Also indicate the total number of sigma and pi bonds in this molecule.

Q46Short answer

Group the following as linear and non-linear molecules : H2O, HOCl, BeCl2, Cl2O

Q47Multiple choice

Elements X, Y and Z have 4, 5 and 7 valence electrons respectively.

  • (i)Write the molecular formula of the compounds formed by these elements individually with hydrogen.
  • (ii)Which of these compounds will have the highest dipole moment?
Q48Multiple choice

Draw the resonating structure of

  • (i)Ozone molecule
  • (ii)Nitrate ion
Q49Short answer

Predict the shapes of the following molecules on the basis of hybridisation. BCl3, CH4, CO2, NH3 2–

Q50Short answer

All the C—O bonds in carbonate ion (CO3 ) are equal in length. Explain.

Q51Short answer

What is meant by the term average bond enthalpy? Why is there difference in bond enthalpy of O—H bond in ethanol (C2H5OH) and water?

Q52Multiple choice

Match the species in Column I with the type of hybrid orbitals in Column II. Column I Column II (i) SF4

  • (a)sp3d2 (ii) IF5
  • (b)d2sp3 + (iii) NO 2
  • (c)sp3d + (iv) NH 4
  • (d)sp3 (e) sp
Q53Multiple choice

Match the species in Column I with the geometry/shape in Column II. Column I Column II + (i) H3O

  • (a)Linear (ii) HC ≡ CH
  • (b)Angular – (iii) ClO 2
  • (c)Tetrahedral + (iv) NH 4
  • (d)Trigonal bipyramidal (e) Pyramidal
Q54Multiple choice

Match the species in Column I with the bond order in Column II. Column I Column II (i) NO

  • (a)1.5 (ii) CO
  • (b)2.0 – (iii) O2
  • (c)2.5 (iv) O2
  • (d)3.0
Q55Multiple choice

Match the items given in Column I with examples given in Column II. Column I Column II (i) Hydrogen bond

  • (a)C (ii) Resonance
  • (b)LiF (iii) Ionic solid
  • (c)H2 (iv) Covalent solid
  • (d)HF (e) O3
Q56Multiple choice

Match the shape of molecules in Column I with the type of hybridisation in Column II. Column I Column II (i) Tetrahedral

  • (a)sp2 (ii) Trigonal
  • (b)sp (iii) Linear
  • (c)sp3
Q57Assertion & reason

Assertion (A): Sodium chloride formed by the action of chlorine gas on sodium metal is a stable compound.

Reason (R): This is because sodium and chloride ions acquire octet in sodium chloride formation. 47 Chemical Bonding and Molecular Structure (i) A and R both are correct, and R is the correct explanation of A. (ii) A and R both are correct, but R is not the correct explanation of A. (iii) A is true but R is false. (iv) A and R both are false.

  • (i)A and R both are correct, and R is the correct explanation of A.
  • (ii)A and R both are correct, but R is not the correct explanation of A.
  • (iii)A is true but R is false.
  • (iv)A and R both are false.
Q58Assertion & reason

Assertion (A): Though the central atom of both NH3 and H2O molecules are sp3 hybridised, yet H–N–H bond angle is greater than that of H–O–H.

Reason (R): This is because nitrogen atom has one lone pair and oxygen atom has two lone pairs. (i) A and R both are correct, and R is the correct explanation of A. (ii) A and R both are correct, but R is not the correct explanation of A. (iii) A is true but R is false. (iv) A and R both are false.

  • (i)A and R both are correct, and R is the correct explanation of A.
  • (ii)A and R both are correct, but R is not the correct explanation of A.
  • (iii)A is true but R is false.
  • (iv)A and R both are false.
Q59Assertion & reason

Assertion (A): Among the two O–H bonds in H2O molecule, the energy required to break the first O–H bond and the other O–H bond is the same.

Reason (R): This is because the electronic environment around oxygen is the same even after breakage of one O–H bond. (i) A and R both are correct, and R is correct explanation of A. (ii) A and R both are correct, but R is not the correct explanation of A. (iii) A is true but R is false. (iv) A and R both are false.

  • (i)A and R both are correct, and R is correct explanation of A.
  • (ii)A and R both are correct, but R is not the correct explanation of A.
  • (iii)A is true but R is false.
  • (iv)A and R both are false.
Q60Multiple choice
  • (i)Discuss the significance/ applications of dipole moment.
  • (ii)Represent diagrammatically the bond moments and the resultant dipole moment in CO2 , NF3 and CHCl3.
Q61Long answer

Use the molecular orbital energy level diagram to show that N2 would be expected to have a triple bond, F2, a single bond and Ne2, no bond.

Q62Long answer

Briefly describe the valence bond theory of covalent bond formation by taking an example of hydrogen. How can you interpret energy changes taking place in the formation of dihydrogen?

Q63Long answer

Describe hybridisation in the case of PCl5 and SF6. The axial bonds are longer as compared to equatorial bonds in PCl5 whereas in SF6 both axial bonds and equatorial bonds have the same bond length. Explain.

Q64Multiple choice

(i) Discuss the concept of hybridisation. What are its different types in a carbon atom. (ii) What is the type of hybridisation of carbon atoms marked with star.

  • (a)
  • (b)
  • (c)
  • (d)(e) Comprehension given below is followed by some multiple choice questions. Each question has one correct option. Choose the correct option. Molecular orbitals are formed by the overlap of atomic orbitals. Two atomic orbitals combine to form two molecular orbitals called bonding molecular orbital (BMO) and anti bonding molecular orbital (ABMO). Energy of anti bonding orbital is raised above the parent atomic orbitals that have combined and the energy of the bonding orbital is lowered than the parent atomic orbitals. Energies of various molecular orbitals for elements hydrogen to nitrogen increase in the order : σ 1s < σ * 1s < σ 2 s < σ * 2 s < ( π 2 p x ≈ π 2 p y ) < σ 2 p z < ( π * 2 p x ≈ π * 2 p y ) < σ * 2 p z and for oxygen and fluorine order of energy of molecular orbitals is given below : σ 1s < σ * 1s < σ 2 s < σ * 2 s < σ 2 p z < ( π 2 p x π 2 p y ) < ( π * 2 p x π * 2 p y ) < σ * 2 p z Different atomic orbitals of one atom combine with those atomic orbitals of the second atom which have comparable energies and proper orientation. Further, if the overlapping is head on, the molecular orbital is called ‘Sigma’, () and if the overlap is lateral, the molecular orbital is called ‘pi’, (). The molecular orbitals are filled with electrons according to the same rules as followed for filling of atomic orbitals. However, the order for filling is not the same for all molecules or their ions. Bond order is one of the most important parameters to compare the strength of bonds.
Q65Multiple choice

Which of the following statements is correct?

  • (i)In the formation of dioxygen from oxygen atoms 10 molecular orbitals will be formed.
  • (ii)All the molecular orbitals in the dioxygen will be completely filled.
  • (iii)Total number of bonding molecular orbitals will not be same as total number of anti bonding orbitals in dioxygen.
  • (iv)Number of filled bonding orbitals will be same as number of filled anti bonding orbitals. 49 Chemical Bonding and Molecular Structure
Q66Multiple choice

Which of the following molecular orbitals has maximum number of nodal planes?

  • (i)σ*1s
  • (ii)σ*2pz
  • (iii)π2px
  • (iv)π*2py
Q67Multiple choice

Which of the following pair is expected to have the same bond order?

  • (i)O2 , N2 + –
  • (ii)O2 , N2 – +
  • (iii)O2 , N2 – –
  • (iv)O2 , N2
Q68Multiple choice

In which of the following molecules, σ2pz molecular orbital is filled after π2px and π2py molecular orbitals?

  • (i)O2
  • (ii)Ne2
  • (iii)N2
  • (iv)F2