Q20Short answer
18.0 g of water completely vapourises at 100°C and 1 bar pressure and the –1 enthalpy change in the process is 40.79 kJ mol . What will be the enthalpy change for vapourising two moles of water under the same conditions? What is the standard enthalphy of vapourisation for water?
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+ 81.58 kJ, ∆vapH = + 40.79 kJ mol