Q23Short answer
The value of ∆f H for NH3 is – 91.8 kJ mol . Calculate enthalpy change for the following reaction : 2NH3(g) → N2(g) + 3H2(g)
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∆r H = +91.8 kJ mol
The value of ∆f H for NH3 is – 91.8 kJ mol . Calculate enthalpy change for the following reaction : 2NH3(g) → N2(g) + 3H2(g)
∆r H = +91.8 kJ mol