Q27Short answer
Given that ∆H = 0 for mixing of two gases. Explain whether the diffusion of these gases into each other in a closed container is a spontaneous process or not?
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It is spontaneous process. Although enthalpy change is zero but randomness or disorder (i.e., ∆ S ) increases. Therefore, in equation ∆G = ∆H – T∆S, the term T∆S will be negative. Hence, ∆G will be negative. qrev