Q49Short answer
1 . 0 m o l o f a m o n oa t o m i c i d e a l g a s i s expanded from state (1) to state (2) as shown in Fig. 6.4. Calculate the work done for the expansion of gas from state (1) to state (2) at 298 K.
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It is clear from the figure that the process has been carried out in infinite steps, hence it is isothermal reversible expansion. V2 w = – 2.303nRT log V V2 p1 2 But, p1V1 = p2V2 ⇒ V = p = =2 1 2 1 p1 ∴ w = – 2.303 nRT log p –1 = – 2.303 × 1 mol × 8.314 J mol K–1 × 298 K–1 × log 2 = – 2.303 × 8.314 × 298 × 0.3010 J = –1717.46 J