Q32Short answer
pH of 0.08 mol dm–3 HOCl solution is 2.85. Calculate its ionisation constant.
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pH of HOCl = 2.85 + But, – pH = log [H ] + ∴ – 2.85 = log [H ] + 3 .15 = log [H ] + [H ] = 1.413 × 10–3 + For weak mono basic acid [H ] = Ka × C + 2 –3 2 [H ] (1.413 × 10 ) Ka = = C 0.08 –6 –5 = 24.957 × 10 = 2.4957 × 10