Q37Short answer
Following data is given for the reaction: CaCO3 (s) → CaO (s) + CO2 (g) V –1 ∆f H [CaO(s)] = – 635.1 kJ mol V –1 ∆f H [CO2(g)] = – 393.5 kJ mol V –1 ∆f H [CaCO3(s)] = – 1206.9 kJ mol Predict the effect of temperature on the equilibrium constant of the above reaction.
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∆rH = ∆f H [CaO(s)] + ∆f H [CO2(g)] – ∆f H [CaCO3(s)] V –1 ∴ ∆rH = 178.3 kJ mol The reaction is endothermic. Hence, according to Le-Chatelier’s principle, reaction will proceed in forward direction on increasing temperature. IV. Matching Type