Q10Short answer
If tanθ + sinθ = m and tanθ – sinθ = n, then prove that m2 – n2 = 4sinθ tanθ [Hint: m + n = 2tanθ, m – n = 2 sinθ, then use m2 – n2 = (m + n) (m – n)] p+q
If tanθ + sinθ = m and tanθ – sinθ = n, then prove that m2 – n2 = 4sinθ tanθ [Hint: m + n = 2tanθ, m – n = 2 sinθ, then use m2 – n2 = (m + n) (m – n)] p+q