Q4Long answer
x –1 ⇒ (8x + 1 < 0 and 4x – 1 > 0) or (8x + 1 > 0 and 4x – 1 < 0) 1 1 1 1 ⇒ (x < − and x > ) or (x > − and x < ) 8 4 8 4 1 1 ⇒ x ∈ (− , ) (Since the first is not possible) ... (2) 8 4 Note that the common solution of (1) and (2) is null set. Hence, the given system of inequalities has no solution.