Which cell will measure standard electrode potential of copper electrode? +
- (i)Pt (s) H2 (g,0.1 bar) H (aq.,1 M) Cu2+(aq.,1M) Cu +
- (ii)Pt(s) H2 (g, 1 bar) H (aq.,1 M) Cu2+ (aq.,2 M) Cu +
- (iii)Pt(s) H2 (g, 1 bar) H (aq.,1 M) Cu2+ (aq.,1 M) Cu +
- (iv)Pt(s) H2 (g, 1 bar) H (aq.,0.1 M) Cu2+ (aq.,1 M) Cu
Show answer
(iii) Pt(s) H2 (g, 1 bar) H (aq.,1 M) Cu2+ (aq.,1 M) Cu +
Electrode potential for Mg electrode varies according to the equation 0 .0 5 9 1 E = E V 2+ – log . The graph of E 2 + vs 2+ Mg | Mg Mg | Mg 2 [Mg 2 + ] Mg | Mg log [Mg2+] is
Show answer
Which of the following statement is correct?
- (i)ECell and ∆rG of cell reaction both are extensive properties.
- (ii)ECell and ∆rG of cell reaction both are intensive properties.
- (iii)ECell is an intensive property while ∆rG of cell reaction is an extensive property.
- (iv)ECell is an extensive property while ∆rG of cell reaction is an intensive property.
Show answer
(iii) ECell is an intensive property while ∆rG of cell reaction is an extensive property.
The difference between the electrode potentials of two electrodes when no current is drawn through the cell is called ___________.
- (i)Cell potential
- (ii)Cell emf
- (iii)Potential difference
- (iv)Cell voltage
Show answer
Which of the following statement is not correct about an inert electrode in a cell?
- (i)It does not participate in the cell reaction.
- (ii)It provides surface either for oxidation or for reduction reaction.
- (iii)It provides surface for conduction of electrons.
- (iv)It provides surface for redox reaction.
Show answer
(iv) It provides surface for redox reaction.
An electrochemical cell can behave like an electrolytic cell when ____________.
- (i)Ecell = 0
- (ii)Ecell > Eext
- (iii)Eext > Ecell
- (iv)Ecell = Eext
Show answer
Which of the statements about solutions of electrolytes is not correct?
- (i)Conductivity of solution depends upon size of ions.
- (ii)Conductivity depends upon viscosiy of solution.
- (iii)Conductivity does not depend upon solvation of ions present in solution.
- (iv)Conductivity of solution increases with temperature.
Show answer
(iii) Conductivity does not depend upon solvation of ions present in solution.
Using the data given below find out the strongest reducing agent. V V E E Cr2O72– /Cr 3+ = 1.33V Cl2 /Cl– = 1.36V V V E = 1.51V E = – 0.74V MnO4– /Mn2+ Cr 3+ /Cr –
- (i)Cl
- (ii)Cr
- (iii)Cr3+
- (iv)Mn2+
Show answer
Use the data given in Q.8 and find out which of the following is the strongest oxidising agent. –
- (i)Cl
- (ii)Mn2+ –
- (iii)MnO4
- (iv)Cr3+
Show answer
Using the data given in Q.8 find out in which option the order of reducing power is correct. 3+ – 2+
- (i)Cr < Cl < Mn < Cr 2+ – 3+
- (ii)Mn < Cl < Cr < Cr 3+ – 2– –
- (iii)Cr < Cl < Cr2O7 < MnO4 2+ 3+ –
- (iv)Mn < Cr < Cl < Cr
Show answer
(ii) Mn < Cl < Cr < Cr 3+ – 2– –
Use the data given in Q.8 and find out the most stable ion in its reduced form. –
- (i)Cl
- (ii)Cr3+
- (iii)Cr
- (iv)Mn2+
Show answer
Use the data of Q.8 and find out the most stable oxidised species.
- (i)Cr3+ –
- (ii)MnO4 2–
- (iii)Cr2O7 2+
- (iv)Mn
Show answer
The quantity of charge required to obtain one mole of aluminium from Al2O3 is ___________.
Show answer
The cell constant of a conductivity cell _____________.
- (i)changes with change of electrolyte.
- (ii)changes with change of concentration of electrolyte.
- (iii)changes with temperature of electrolyte.
- (iv)remains constant for a cell.
Show answer
(iv) remains constant for a cell.
While charging the lead storage battery ______________.
- (i)PbSO4 anode is reduced to Pb.
- (ii)PbSO4 cathode is reduced to Pb. 35 Electrochemistry
- (iii)PbSO4 cathode is oxidised to Pb.
- (iv)PbSO4 anode is oxidised to PbO2.
Show answer
(i) PbSO4 anode is reduced to Pb.
Λm (NH OH) is equal to ______________. 0 0 0
- (i)Λm (NH OH) + Λm (NH Cl) – Λ (HCl) 4 4 0 0 0
- (ii)Λm (NH Cl) + Λm (NaOH) – Λ(NaCl) 0 0 0
- (iii)Λm (NH Cl) + Λm (NaCl) – Λ(NaOH) 0 0 0
- (iv)Λm (NaOH) + Λm (NaCl) – Λ(NH Cl)
Show answer
(ii) Λm (NH Cl) + Λm (NaOH) – Λ(NaCl) 0 0 0
In the electrolysis of aqueous sodium chloride solution which of the half cell reaction will occur at anode?
- (i)Na+ (aq) + e– → Na (s); E Cell = –2.71V + V
- (ii)2H2O (l) → O2 (g) + 4H (aq) + 4e– ; E Cell = 1.23V + 1 V
- (iii)H (aq) + e– → H (g); E Cell = 0.00 V 2 2 – 1 V
- (iv)Cl (aq) → Cl (g) + e– ; E Cell = 1.36 V 2 2
Show answer
(ii) 2H2O (l) → O2 (g) + 4H (aq) + 4e– ; E Cell = 1.23V + 1 V
The positive value of the standard electrode potential of Cu2+/Cu indicates that ____________. +
- (i)this redox couple is a stronger reducing agent than the H /H2 couple. +
- (ii)this redox couple is a stronger oxidising agent than H /H2.
- (iii)Cu can displace H2 from acid.
- (iv)Cu cannot displace H2 from acid.
Show answer
(ii) this redox couple is a stronger oxidising agent than H /H2.
(iv) Cu cannot displace H2 from acid.
E Cell for some half cell reactions are given below. On the basis of these mark the correct answer. + 1 V (a) H (aq) + e– → H (g) ; E Cell = 0.00V 2 2 + V (b) 2H2O (l) → O2 (g) + 4H (aq) + 4e– ; E Cell = 1.23V 2– 2– V (c) 2SO4 (aq) → S2O8 (aq) + 2e– ; E Cell = 1.96 V
- (i)In dilute sulphuric acid solution, hydrogen will be reduced at cathode.
- (ii)In concentrated sulphuric acid solution, water will be oxidised at anode.
- (iii)In dilute sulphuric acid solution, water will be oxidised at anode. 2–
- (iv)In dilute sulphuric acid solution, SO4 ion will be oxidised to tetrathionate ion at anode.
Show answer
(i) In dilute sulphuric acid solution, hydrogen will be reduced at cathode.
(iii) In dilute sulphuric acid solution, water will be oxidised at anode. 2–
E Cell = 1.1V for Daniel cell. Which of the following expressions are correct description of state of equilibrium in this cell?
- (i)1.1 = Kc 2.303RT
- (ii)logK c =1.1 2F 2.2
- (iii)log Kc = 0.059
- (iv)log Kc = 1.1
Show answer
(ii) logK c =1.1 2F 2.2
(iii) log Kc = 0.059
Conductivity of an electrolytic solution depends on ____________.
- (i)nature of electrolyte.
- (ii)concentration of electrolyte.
- (iii)power of AC source.
- (iv)distance between the electrodes.
Show answer
(i) nature of electrolyte.
(ii) concentration of electrolyte.
Λm H2 O is equal to _______________. 0 0 0
- (i)Λm (HCl) + Λm (NaOH) – Λm (NaCl) 0 0 0
- (ii)Λm (HNO ) + Λm (NaNO ) – Λ m (NaOH) 3 3 0 0 0
- (iii)Λ(HNO ) + Λm (NaOH) – Λm (NaNO ) 3 3 0 0 0
- (iv)Λm (NH OH) + Λm (HCl) – Λm (NH Cl) 4 4
Show answer
(i) Λm (HCl) + Λm (NaOH) – Λm (NaCl) 0 0 0
(iv) Λm (NH OH) + Λm (HCl) – Λm (NH Cl) 4 4
What will happen during the electrolysis of aqueous solution of CuSO4 by using platinum electrodes?
- (i)Copper will deposit at cathode.
- (ii)Copper will deposit at anode. 37 Electrochemistry
- (iii)Oxygen will be released at anode.
- (iv)Copper will dissolve at anode.
Show answer
(i) Copper will deposit at cathode.
(iii) Oxygen will be released at anode.
What will happen during the electrolysis of aqueous solution of CuSO4 in the presence of Cu electrodes?
- (i)Copper will deposit at cathode.
- (ii)Copper will dissolve at anode.
- (iii)Oxygen will be released at anode.
- (iv)Copper will deposit at anode.
Show answer
(i) Copper will deposit at cathode.
(ii) Copper will dissolve at anode.
Conductivity κ , is equal to ____________. 1 l
Show answer
Molar conductivity of ionic solution depends on ___________.
- (i)temperature.
- (ii)distance between electrodes.
- (iii)concentration of electrolytes in solution.
- (iv)surface area of electrodes.
Show answer
(i) temperature.
(iii) concentration of electrolytes in solution.
For the given cell, Mg|Mg2+|| Cu2+|Cu
- (i)Mg is cathode
- (ii)Cu is cathode
- (iii)The cell reaction is Mg + Cu2+ → Mg2+ + Cu
- (iv)Cu is the oxidising agent
Show answer
(ii) Cu is cathode
(iii) The cell reaction is Mg + Cu2+ → Mg2+ + Cu
Can absolute electrode potential of an electrode be measured? V V
Show answer
Can E Cell or ∆r G for cell reaction ever be equal to zero?
Show answer
Under what condition is ECell = 0 or ∆ rG = 0?
Show answer
When the cell reaction reaches equilibrium.
What does the negative sign in the expression E = − 0.76 V mean? Zn2+/Zn
Show answer
It means that Zn is more reactive than hydrogen. When zinc electrode will be connected to SHE, Zn will get oxidised and H+ will get reduced.
Aqueous copper sulphate solution and aqueous silver nitrate solution are electrolysed by 1 ampere current for 10 minutes in separate electrolytic cells. Will the mass of copper and silver deposited on the cathode be same or different? Explain your answer.
Show answer
Different, see the NCERT textbook, page no. 84.
Depict the galvanic cell in which the cell reaction is Cu + 2Ag+ → 2Ag + Cu2+ –
Show answer
Value of standard electrode potential for the oxidation of Cl ions is more positive than that of water, even then in the electrolysis of aqueous sodium – chloride, why is Cl oxidised at anode instead of water?
Show answer
Under the conditions of electrolysis of aqueous sodium chloride, oxidation – of water at anode requires overpotential hence Cl is oxidised instead of water.
What is electrode potential?
Show answer
See NCERT textbook, page no. 65
Consider the following diagram in which an electrochemical cell is coupled to an electrolytic cell. What will be the polarity of electrodes ‘A’ and ‘B’ in the electrolytic cell? Fig. 3.1
This question refers to a figure in the original PDF.
Show answer
‘A’ will have negative polarity ‘B’ will have positive polarity
Why is alternating current used for measuring resistance of an electrolytic solution?
Show answer
Alternating current is used to prevent electrolysis so that concentration of ions in the solution remains constant.
A galvanic cell has electrical potential of 1.1V. If an opposing potential of 1.1V is applied to this cell, what will happen to the cell reaction and current flowing through the cell?
Show answer
See NCERT textbook, page no. 64
How will the pH of brine (aq. NaCl solution) be affected when it is electrolysed?
Show answer
The pH of the solution will rise as NaOH is formed in the electrolytic cell.
Unlike dry cell, the mercury cell has a constant cell potential throughout its useful life. Why?
Show answer
Ions are not involved in the overall cell reaction of mercury cells.
Solutions of two electrolytes ‘A’ and ‘B’ are diluted. The Λ m of ‘B’ increases 1.5 times while that of A increases 25 times. Which of the two is a strong electrolyte? Justify your answer. 39 Electrochemistry
Show answer
Electrolyte ‘B’ is strong as on dilution the number of ions remains the same, only interionic attraction decreases therefore increase in ∧m is small. +
When acidulated water (dil.H2SO4 solution) is electrolysed, will the pH of the solution be affected? Justify your answer.
Show answer
pH of the solution will not be affected as [H ] remains constant. + At anode : 2H2O → O2 + 4H + 4e– + At cathode 4H + 4e– → 2H2
In an aqueous solution how does specific conductivity of electrolytes change with addition of water?
Show answer
Conductivity decreases because number of ions per unit volume decreases.
Which reference electrode is used to measure the electrode potential of other electrodes?
Show answer
Standard hydrogen electrode is the reference electrode whose electrode potential is taken to be zero. The electrode potential of other electrodes is measured with respect to it.
Consider a cell given below — Cu|Cu2+||Cl |Cl2,Pt Write the reactions that occur at anode and cathode
Show answer
Anode : Cu → Cu2+ + 2e– – Cathode : Cl2 + 2e– → 2Cl Cu is anode as it is getting oxidised. Cl2 is cathode as it is getting reduced.
Write the Nernst equation for the cell reaction in the Daniel cell. How will the ECell be affected when concentration of Zn2+ ions is increased?
Show answer
Zn + Cu2+ → Zn2+ + Cu 2+ V 0.059 [Zn ] ECell = E Cell – log 2+ 2 [Cu ] 2+ ECell decreases when concentration of Zn ions, [Zn2+] increases.
What advantage do the fuel cells have over primary and secondary batteries?
Show answer
Primary batteries contain a limited amount of reactants and are discharged when the reactants have been consumed. Secondary batteries can be recharged but take a long time to recharge. Fuel cell runs continuously as long as the reactants are supplied to it and products are removed continuously.
Write the cell reaction of a lead storage battery when it is discharged. How does the density of the electrolyte change when the battery is discharged?
Show answer
Pb + PbO2 + 2H2SO4 → 2PbSO4 + 2H2O Density of electrolyte decreases as water is formed and sulphuric acid is consumed as the product during discharge of the battery.
Why on dilution the Λ m of CH3COOH increases drastically, while that of CH3COONa increases gradually?
Show answer
In the case of CH3COOH, which is a weak electrolyte, the number of ions increase on dilution due to an increase in degree of dissociation. — + CH3COOH + H2O CH3COO + H3O In the case of strong electrolyte the number of ions remains the same but the interionic attraction decreases. IV. Matching Type
Match the terms given in Column I with the units given in Column II. Column I Column II (i) ∧m
- (a)S cm–1 (ii) ECell
- (b)m–1 (iii) κ
- (c)S cm2 mol–1 (iv) G*
- (d)V
Show answer
(a) S cm–1 (ii) ECell
(c) S cm2 mol–1 (iv) G*
(b) m–1 (iii) κ
(d) V
Match the terms given in Column I with the items given in Column II. Column I Column II (i) Λm
- (a)intensive property (ii) E Cell
- (b)depends on number of ions/volume (iii) κ
- (c)extensive property (iv) ∆rGCell
- (d)increases with dilution
Show answer
(a) intensive property (ii) E Cell
(d) increases with dilution
(b) depends on number of ions/volume (iii) κ
(c) extensive property (iv) ∆rGCell
Match the items of Column I and Column II. Column I Column II (i) Lead storage battery
- (a)maximum efficiency (ii) Mercury cell
- (b)prevented by galvanisation (iii) Fuel cell
- (c)gives steady potential (iv) Rusting
- (d)Pb is anode, PbO2 is cathode
Show answer
(a) maximum efficiency (ii) Mercury cell
(d) Pb is anode, PbO2 is cathode
(b) prevented by galvanisation (iii) Fuel cell
(c) gives steady potential (iv) Rusting
Match the items of Column I and Column II. Column I Column II (i) κ
- (a)I×t (ii) Λm
- (b)Λm / Λ0 κ (iii) α
- (c)G* (iv) Q
- (d)
Show answer
(a) I×t (ii) Λm
(d)
(b) Λm / Λ0 κ (iii) α
(c) G* (iv) Q
Match the items of Column I and Column II. Column I Column II (i) Lechlanche cell
- (a)cell reaction 2H2 + O2 → 2H2O (ii) Ni–Cd cell
- (b)does not involve any ion in solution and is used in hearing aids. (iii) Fuel cell
- (c)rechargeable (iv) Mercury cell
- (d)reaction at anode, Zn → Zn2+ + 2e– (e) converts energy of combustion into electrical energy
Show answer
(a) cell reaction 2H2 + O2 → 2H2O (ii) Ni–Cd cell
(d) reaction at anode, Zn → Zn2+ + 2e– (e) converts energy of combustion into electrical energy
(b) does not involve any ion in solution and is used in hearing aids. (iii) Fuel cell
(c) rechargeable (iv) Mercury cell
Match the items of Column I and Column II on the basis of data given below: V V V E = 2.87V , E V + = −3.5V , E = 1.4V , E Br /Br – = 1.09V F /F – Li /Li Au3+/Au 2 Column I Column II (i) F2
- (a)metal is the strongest reducing agent (ii) Li
- (b)metal ion which is the weakest oxidising agent (iii) Au3+
- (c)non metal which is the best oxidising agent – (iv) Br
- (d)unreactive metal (v) Au (e) anion that can be oxidised by Au3+ + (vi) Li (f) anion which is the weakest reducing agent – (vii) F (g) metal ion which is an oxidising agent 41 Electrochemistry
Show answer
(a) metal is the strongest reducing agent (ii) Li
(c) non metal which is the best oxidising agent – (iv) Br
(b) metal ion which is the weakest oxidising agent (iii) Au3+
(d) unreactive metal (v) Au (e) anion that can be oxidised by Au3+ + (vi) Li (f) anion which is the weakest reducing agent – (vii) F (g) metal ion which is an oxidising agent 41 Electrochemistry
Assertion (A): Cu is less reactive than hydrogen.
Reason (R): E is negative. Cu2+ /Cu
Show answer
Assertion (A): E Cell should have a positive value for the cell to function.
Reason (R): Ecathode < Eanode
Show answer
Assertion (A): Conductivity of all electrolytes decreases on dilution.
Reason (R): On dilution number of ions per unit volume decreases.
Show answer
Assertion (A): Λm for weak electrolytes shows a sharp increase when the electrolytic solution is diluted.
Reason (R): For weak electrolytes degree of dissociation increases with dilution of solution.
Show answer
Assertion (A): Mercury cell does not give steady potential.
Reason (R): In the cell reaction, ions are not involved in solution.
Show answer
Assertion (A): Electrolysis of NaCl solution gives chlorine at anode instead of O2.
Reason (R): Formation of oxygen at anode requires overvoltage.
Show answer
Assertion (A): For measuring resistance of an ionic solution an AC source is used.
Reason (R): Concentration of ionic solution will change if DC source is used.
Show answer
Assertion (A): Current stops flowing when ECell = 0.
Reason (R): Equilibrium of the cell reaction is attained.
Show answer
Assertion (A): E + Ag+/Ag increases with increase in concentration of Ag ions.
Reason (R): E Ag+/Ag has a positive value.
Show answer
Assertion (A): Copper sulphate can be stored in zinc vessel.
Reason (R): Zinc is less reactive than copper.
Show answer
Consider the Fig. 3.2 and answer the following questions. Fig. 3.2
This question refers to a figure in the original PDF.
- (i)Cell ‘A’ has ECell = 2V and Cell ‘B’ has ECell = 1.1V which of the two cells ‘A’ or ‘B’ will act as an electrolytic cell. Which electrode reactions will occur in this cell?
- (ii)If cell ‘A’ has ECell = 0.5V and cell ‘B’ has ECell = 1.1V then what will be the reactions at anode and cathode?
Show answer
(i) Cell ‘A’ has ECell = 2V and Cell ‘B’ has ECell = 1.1V which of the two cells ‘A’ or ‘B’ will act as an electrolytic cell. Which electrode reactions will occur in this cell?
(ii) If cell ‘A’ has ECell = 0.5V and cell ‘B’ has ECell = 1.1V then what will be the reactions at anode and cathode?
Consider Fig. 3.2 and answer the questions
This question refers to a figure in the original PDF.
- (i)to (vi) given below. (i) Redraw the diagram to show the direction of electron flow.
- (ii)Is silver plate the anode or cathode?
- (iii)What will happen if salt bridge is removed?
- (iv)When will the cell stop functioning? Fig. 3.3 (v) How will concentration of Zn2+ ions and Ag+ ions be affected when the cell functions? (vi) How will the concentration of Zn2+ ions and Ag+ ions be affected after the cell becomes ‘dead’?
Show answer
Hint : (i) Electrons move from Zn to Ag. (ii) Ag is the cathode. (iii) Cell will stop functioning. (iv) When E Cell = 0. (v) Concentration of Zn2+ ions will increase and concentration of Ag+ ions will decrease (vi) When E cell = 0 equilibrium is reached and concentration of 2+ Zn ions and Ag + ions will not change.
What is the relationship between Gibbs free energy of the cell reaction in a galvanic cell and the emf of the cell? When will the maximum work be obtained from a galvanic cell? 43 Electrochemistry