Q71Long answer
On heating lead (II) nitrate gives a brown gas “A”. The gas “A” on cooling changes to colourless solid “B”. Solid “B” on heating with NO changes to a blue solid ‘C’. Identify ‘A’, ‘B’ and ‘C’ and also write reactions involved and draw the structures of ‘B’ and ‘C’.
Show answer
Pb(NO3)2 2PbO + 4NO2 673K (A) (Brown colour) On cooling 2NO2 Heating N2O4 (B) (Colourless solid) ∆ 250 K 2NO + N2O4 → 2 N2O3 (C) (Blue solid) (Structure of N2O4) (Structure of N2O3)