Q4Multiple choice
When 1 mol CrCl3⋅6H2O is treated with excess of AgNO3, 3 mol of AgCl are obtained. The formula of the complex is :
- (i)[CrCl3 (H2O)3]⋅3H2O
- (ii)[CrCl2(H2O)4]Cl⋅2H2O
- (iii)[CrCl(H2O)5]Cl2⋅H2O
- (iv)[Cr(H2O)6]Cl3
Show answer
(iv) [Cr(H2O)6]Cl3