Question 42

Let f : R → R be defined by f (x) = 3x2 – 5 and g : R → R by g (x) = . x +1 Then g o f is 3 x 2 −5 3 x 2 −5

• (A)
• (B)9 x 4 − 30 x 2 + 26 9 x 4 − 6 x 2 + 26 3x 2 3x 2
• (C)
• (D)x4 + 2 x2 − 4 9 x 4 + 30 x 2 − 2