Question 67

If P(B) = , P(A | B) = and P(A ∪ B) = , then P(A ∪ B )′ + P( A′ ∪ B) = 5 2 5 1 4 1

• (A)
• (B)
• (C)
• (D)1 5 5 2 PROBABILITY 281 7 9 4