Q30Multiple choice
MATHEMATICS 1 1− x 2 (C) (D) . x x Solution (D) is the correct answer. Let sin–1 x = θ, then sinθ = x 1 1 ⇒ cosec θ = ⇒ cosec2θ = x x2 1 1− x 2 ⇒ 1 + cot2 θ = ⇒ cotθ = . x2 x π
MATHEMATICS 1 1− x 2 (C) (D) . x x Solution (D) is the correct answer. Let sin–1 x = θ, then sinθ = x 1 1 ⇒ cosec θ = ⇒ cosec2θ = x x2 1 1− x 2 ⇒ 1 + cot2 θ = ⇒ cotθ = . x2 x π