Question 69

On using elementary row operation R1 → R1 – 3R2 in the following matrix equation:  4 2 1 2  2 0  3 3 =  0 3  1 1  , we have :        −5 −7   1 −7   2 0 

• (A)3 3   0 3   1 1  =   −5 −7  1 2  −1 −3
• (B)3 3   0 3  1 1  =   −5 −7  1 2   2 0
• (C)3 3  1 −7   1 1  =  4 2   1 2   2 0
• (D) −5 −7  =  −3 −3  1 1        Fill in the blanks in each of the Exercises 68–81.