Question 41

If ∫ = a (1 + x 2 ) 2 + b 1 + x 2 + C, then 1 + x2 1 –1

• (A)a = , b=1
• (B)a = , b=1 3 3 –1 1
• (C)a = , b = –1
• (D)a = , b = –1 3 3 INTEGRALS 169 π