Question 49

tan–1 x + tan–1 y = c is the general solution of the differential equation: dy 1 + y 2 dy 1 + x 2

• (A)=
• (B)= dx 1 + x 2 dx 1 + y 2
• (C)(1 + x2) dy + (1 + y2) dx = 0
• (D)(1 + x2) dx + (1 + y2) dy = 0