Question 74

The general solution of the differential equation (ex + 1) ydy = (y + 1) exdx is:

• (A)(y + 1) = k (ex + 1)
• (B)y + 1 = ex + 1 + k  e x + 1
• (C)y = log {k (y + 1) (e + 1)}
• (D)y = log  +k  y +1  dy x–y