Q106Short answer
In Fig. 6.29, AD ⊥ BC and AD is the bisector of angle BAC. Then, ∆ABD ≅ ∆ACD by RHS. Fig. 6.29
This question refers to a figure in the original PDF.
Show answer
False
In Fig. 6.29, AD ⊥ BC and AD is the bisector of angle BAC. Then, ∆ABD ≅ ∆ACD by RHS. Fig. 6.29
This question refers to a figure in the original PDF.
False