Which of the following is not equal to ? 6
Chapter 1 – Number Systems
Class 9 Mathematics · 46 questions · 32 with answers
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Are there two irrational numbers whose sum and product both are rationals? Justify.
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Solution : Yes.
State whether the following statement is true: There is a number x such that x2 is irrational but x4 is rational. Justify your answer by an example.
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Solution : True. Let us take x = 4 2 Now, x2 = ( 4 2 ) = 2 , an irrational number. x4 = ( 4 2 ) = 2 , a rational number. So, we have a number x such that x2 is irrational but x4 is rational.
Locate 13 on the number line.
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Solution : We write 13 as the sum of the squares of two natural numbers :
Express 0.123 in the form , where p and q are integers and q ≠ 0.
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Solution : Let x = 0.123 so, 10x = 1.23 or 10x – x = 1.23 – 0.123 = 1.2333 ... – 0.12333 ... or 9x = 1.11 1.11 111 or x= = 9 900 111 37 Therefore, 0.123 = 900 = 300
Simplify : ( 3 5 − 5 2 ) ( 4 5 + 3 2 ) . ( )(
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Solution : 3 5 – 5 2 4 5 + 3 2 ) = 12 × 5 − 20 2 × 5 + 9 5 × 2 – 15 × 2 = 60 − 20 10 + 9 10 – 30 = 30 − 11 10
Find the value of a in the following : = 3 2−a 3 3 2 −2 3 6 6 3 2+2 3
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Solution : = × 3 2 −2 3 3 2 −2 3 3 2+2 3 6 (3 2 + 2 3 ) 6 (3 2 + 2 3 ) 6 (3 2 + 2 3 ) = 2 2 = = (3 2 ) − ( 2 3 ) 18 − 12 6 = 3 2+2 3 Therefore, 3 2+2 3 = 3 2−a 3 or a=–2
Simplify : 13 1 34 ( 5 8 + 27 3 )
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Solution : 1 1 1 3 = 3 4 ( 1 5 8 3 + 27 3 ) ( 1 5 (23 ) 3 + (33 ) 3 ) NUMBER SYSTEMS 9 = 5 ( 2 + 3)3 4 = 5 ( 5 )3 4 = [5 4 ] 4 = 5
If a = 5 + 2 6 and b = , then what will be the value of a2 + b2 ?
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Solution : a = 5 + 2 6
Questions
1 1 6 1 1 – – 5 5 6 5 5 6 30 5 30
- (A)
- (B)
- (C)
- (D)6 6 5 6 Solution : Answer (A)
Every rational number is
- (A)a natural number
- (B)an integer
- (C)a real number
- (D)a whole number NUMBER SYSTEMS 3
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(C) a real number
Between two rational numbers
- (A)there is no rational number
- (B)there is exactly one rational number
- (C)there are infinitely many rational numbers
- (D)there are only rational numbers and no irrational numbers
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(C) there are infinitely many rational numbers
Decimal representation of a rational number cannot be
- (A)terminating
- (B)non-terminating
- (C)non-terminating repeating
- (D)non-terminating non-repeating
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(D) non-terminating non-repeating
The product of any two irrational numbers is
- (A)always an irrational number
- (B)always a rational number
- (C)always an integer
- (D)sometimes rational, sometimes irrational
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(D) sometimes rational, sometimes irrational
The decimal expansion of the number 2 is
- (A)a finite decimal
- (B)1.41421
- (C)non-terminating recurring
- (D)non-terminating non-recurring
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(D) non-terminating non-recurring
Which of the following is irrational? 4 12
- (A)
- (B)
- (C)7
- (D)81
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(C) 7
3 7. Which of the following is irrational?
- (A)0.14
- (B)0.1416
- (C)0.1416
- (D)0.4014001400014... 8. A rational number between 2 and 3 is 2+ 3 2⋅ 3 (A) (B) (C) 1.5 (D) 1.8 2 2 9. The value of 1.999... in the form q , where p and q are integers and q ≠ 0 , is 19 1999 1 (A) (B) (C) 2 (D)
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(C) 0.1416
1000 9 10. 2 3 + 3 is equal to
- (A)2 6
- (B)6
- (C)3 3
- (D)4 6
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(C) 3 3
10 × 15 is equal to
- (A)6 5
- (B)5 6
- (C)25
- (D)10 5
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(B) 5 6
The number obtained on rationalising the denominator of is 7 –2 7+2 7 –2 7+2 7+2
- (A)
- (B)
- (C)
- (D)3 3 5 45
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(A)
is equal to 9– 8
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(D)
1
- (A)(3–2 2 )
- (B)3+ 2 2
- (C)3– 2 2
- (D)3+ 2 2 14. After rationalising the denominator of , we get the denominator as 3 3–2 2 (A) 13 (B) 19 (C) 5 (D) 35 32 + 48 15. The value of is equal to 8 + 12 (A) 2 (B) 2 (C) 4 (D) 8 2 –1 16. If 2 = 1.4142, then is equal to 2 +1 NUMBER SYSTEMS 5 (A) 2.4142 (B) 5.8282 (C) 0.4142 (D) 0.1718 17. 4 3 22 equals
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(C) 3– 2 2
1
- (A)−
- (B)2– 6
- (C)
- (D)26
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(C)
6 26 18. The product 3 2 ⋅ 4 2 ⋅ 12 32 equals
- (A)
- (B)2
- (C)
- (D)12 2 12 2 32 −2 19. Value of 4 (81) is
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(C)
1 1
- (A)
- (B)
- (C)9
- (D)9 3 81 20. Value of (256)0.16 × (256)0.09 is (A) 4 (B) 16 (C) 64 (D) 256.25 21. Which of the following is equal to x? 1 2 12 5 12 7 (A) 7 x –x 7 (B) 12 (x ) 4 3 (C) ( ) x3 3 (D) x 7 × x12
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(C) 9
+ 2 and 3 − 2 are two irrational numbers. ( 3 + 2 ) + (3 − 2 ) = 6 , a rational number. ( 3 + 2 ) × ( 3 − 2 ) = 7 , a rational number. So, we have two irrational numbers whose sum and product both are rationals.
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(D)
Let x and y be rational and irrational numbers, respectively. Is x + y necessarily an irrational number? Give an example in support of your answer.
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Yes. Let x = 21, y = 2 be a rational number. Now x + y = 21 + 2 = 21 + 1.4142 ... = 22.4142 ... Which is non-terminating and non-recurring. Hence x + y is irrational.
Let x be rational and y be irrational. Is xy necessarily irrational? Justify your answer by an example.
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No. 0 × 2 = 0 which is not irrational . 2 p
State whether the following statements are true or false? Justify your answer.
- (i)is a rational number.
- (ii)There are infinitely many integers between any two integers.
- (iii)Number of rational numbers between 15 and 18 is finite.
- (iv)There are numbers which cannot be written in the form q , q ≠ 0 , p, q both are integers. (v) The square of an irrational number is always rational. (vi) is not a rational number as 12 and 3 are not integers. 15 p (vii) is written in the form , q ≠ 0 and so it is a rational number. 3 q
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(i) is a rational number.
(ii) There are infinitely many integers between any two integers.
(iii) Number of rational numbers between 15 and 18 is finite.
(iv) There are numbers which cannot be written in the form q , q ≠ 0 , p, q both are integers. (v) The square of an irrational number is always rational. (vi) is not a rational number as 12 and 3 are not integers. 15 p (vii) is written in the form , q ≠ 0 and so it is a rational number. 3 q
Classify the following numbers as rational or irrational with justification : 9 28
- (i)196
- (ii)3 18
- (iii)
- (iv)27 343 NUMBER SYSTEMS 7 (v) – 0.4 (vi) (vii) 0.5918 (viii) (1 + 5 ) – ( 4 + 5 ) (ix) 10.124124... (x) 1.010010001...
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(i) 196
(ii) 3 18
(iii)
(iv) 27 343 NUMBER SYSTEMS 7 (v) – 0.4 (vi) (vii) 0.5918 (viii) (1 + 5 ) – ( 4 + 5 ) (ix) 10.124124... (x) 1.010010001...
= 9 + 4 = 32 + 22 On the number line, take OA = 3 units. Draw BA = 2 units, perpendicular to OA. Join OB (see Fig.1.1). By Pythagoras theorem, OB = 13 Using a compass with centre O and radius OB, draw an arc which intersects the number line at the Fig. 1.1 point C. Then, C corresponds to 13 . Remark : We can also take OA = 2 units and AB = 3 units.
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Find which of the variables x, y, z and u represent rational numbers and which irrational numbers :
- (i)x2 = 5
- (ii)y2 = 9
- (iii)z2 = .04
- (iv)u2 =
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(ii) y2 = 9
(iii) z2 = .04
(i) x2 = 5
(iv) u2 =
Find three rational numbers between
- (i)–1 and –2
- (ii)0.1 and 0.11
6 1 1 (iii) and (iv) and
7 4 5 3. Insert a rational number and an irrational number between the following : 1 1
- (i)2 and 3
- (ii)0 and 0.1
- (iii)and 3 2 –2 1
- (iv)and (v) 0.15 and 0.16 (vi) 2 and 3 5 2 (vii) 2.357 and 3.121 (viii) .0001 and .001 (ix) 3.623623 and 0.484848 (x) 6.375289 and 6.375738 4. Represent the following numbers on the number line : –3 –12 7, 7.2, , 2 5 5. Locate 5, 10 and 17 on the number line. 6. Represent geometrically the following numbers on the number line : (i) 4.5 (ii) 5.6 (iii) 8.1 (iv) 2.3 7. Express the following in the form q , where p and q are integers and q ≠ 0 : (i) 0.2 (ii) 0.888... (iii) 5.2 (iv) 0.001 (v) 0.2555... (vi) 0.134 (vii) .00323232... (viii) .404040...
Show that 0.142857142857... =
Simplify the following: 24 54
- (i)45 – 3 20 + 4 5
- (ii)+ 8 9
- (iii)12 × 7 6
- (iv)4 28 ÷ 3 7 ÷ 3 7 7 2 (v) 3 3 + 2 27 + (vi) ( 3 – 2) 3 1 (vii) 4 81 – 8 3 216 + 15 5 32 + 225 (viii) + 8 2 2 3 3 (ix) – 3 6
Rationalise the denominator of the following: 2 40 3+ 2
- (i)
- (ii)
- (iii)3 3 3 4 2 16 2+ 3 6
- (iv)(v) (vi) 41 – 5 2– 3 2+ 3 3+ 2 3 5+ 3 4 3+5 2 (vii) (viii) (ix) 3– 2 5– 3 48 + 18
Find the values of a and b in each of the following: 5+ 2 3
- (i)=a−6 3 7+4 3 NUMBER SYSTEMS 11 3– 5 19
- (ii)=a 5– 3+ 2 5 11 2+ 3
- (iii)= 2–b 6 3 2 –2 3 7+ 5 7– 5 7
- (iv)– =a+ 5b 7– 5 7+ 5 11
If a = 2 + 3 , then find the value of a – .
Rationalise the denominator in each of the following and hence evaluate by taking 2 = 1.414 , 3 = 1.732 and 5 = 2.236 , upto three places of decimal. 4 6 10 – 5
- (i)
- (ii)
- (iii)3 6 2 2 1
- (iv)(v) 2+ 2 3+ 2
Simplify : 4 −12 6
3 8 32 (i) (1 + 2
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Rational numbers: (ii), (iii) Irrational numbers: (i), (iv)
3 + 33 2 ) (ii) 5 5 5 1 2 1 − − 4 −2 2 (iii)
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(i) 2.1, 2.040040004 ... (ii) 0.03, 0.007000700007, ... (iii) , 0.414114111 ... (iv) 0, 0.151151115 ... (v) 0.151, 0.151551555 ... (vi) 1.5, 1.585585558 ... (vii) 3, 3.101101110 ... (viii) 0.00011, .0001131331333 ... (ix) 1, 1.909009000 ... (x) 6.3753, 6.375414114111 ... 1 8 47 1 23 7. (i) (ii) (iii) (iv) (v) 5 9 9 999 90 133 8 40 (vi) (vii) (viii) 990 2475 99 7 6 8 34 3 9. (i) 5 (ii) (iii) 168 2 (iv) (v) 12 3 3 5 3 (vi) 5 − 2 6 (vii) 0 (viii) 2 (ix) 4 2 2 2 2+3 2 10. (i) 3 (ii) 30 (iii) (iv) 41 + 5 9 3 8 (v) 7 + 4 3 (vi) 3 2 − 2 3 (vii) 5 + 2 6 (viii) 9 + 2 15 9+4 6 (ix) 9 −5 11. (i) a = 11 (ii) a = (iii) b = (iv) a = 0, b = 1 11 6 12. 2 3 13. (i) 2.309 (ii) 2.449 (iii) 0.463 (iv) 0.414 (v) 0.318 PNPS 14. (i) 6 (ii) (iii) 9 (iv) 5 (v) 3– 3 (vi) –3 (vii) 16 ANSWERS 153
3 (iv) ( 625)
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Rational numbers: (ii), (iii) Irrational numbers: (i), (iv)
1 − 1 1 2 9 3 × 27 2 − (v) 1 2 (vi) 64 3 64 3 – 64 3 − 36 × 3 3
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Rational numbers: (ii), (iii) Irrational numbers: (i), (iv)
1 8 3 × 16 3 (vii) − 32 3
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Rational numbers: (ii), (iii) Irrational numbers: (i), (iv)
1 1 5−2 6 5−2 6 5−2 6 b= = = × = 2 2 = =5−2 6 a 5+2 6 5 + 2 6 5 − 2 6 5 − (2 6) 25 − 24 Therefore, a2 + b2 = (a + b)2 – 2ab Here, a + b = (5 + 2 6 ) + (5 – 2 6 ) = 10 ab = (5 + 2 6 ) (5 – 2 6 ) = 52 – ( 2 6 )2 = 25 – 24 = 1 Therefore, a2 + b2 = 102 – 2 × 1 = 100 – 2 = 98
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Rational numbers: (ii), (iii) Irrational numbers: (i), (iv)
Express 0.6 + 0.7 + 0.47 in the form , where p and q are integers and q ≠ 0 . 7 3 2 5 3 2
Simplify : – – . 10 + 3 6+ 5 15 + 3 2 4 3
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1
If 2 = 1.414, 3 = 1.732 , then find the value of + . 3 3–2 2 3 3+2 2 3+ 5 2 1
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2.063
If a = , then find the value of a + 2 . 2 a 3+ 2 3– 2
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7
If x = and y = , then find the value of x2 + y2. 3– 2 3+ 2 ( ) −3 − 42
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98
Simplify : ( 256 ) 4 1 2
Find the value of 2 + 3 + 1 − − ( ) 216 3 ( ) 256 4 ( 243)− 5
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214