Q42Long answer
A silver ornament of mass ‘m’ gram is polished with gold equivalent to 1% of the mass of silver. Compute the ratio of the number of atoms of gold and silver in the ornament.
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Mass of silver = m g Mass of gold = g Mass Number of atoms of silver = × NA Atomic mass = × NA Number of atoms of gold = ×NA 100 ×197 Ratio of number of atoms of gold to silver = Au : Ag m m = × NA : × NA 100 ×197 108 = 108 : 100×197 = 108 : 19700 =1 : 182.41 16 g