Q24Long answer
Two stones are thrown vertically upwards simultaneously with their initial velocities u1 and u2 respectively. Prove that the heights reached by them would be in the ratio of u 12 : u 22 ( Assume upward acceleration is –g and downward acceleration to be +g ). 16-04-2018
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We know for upward motion, v 2 = u2 – 2 g h or h = 2g But at highest point v = 0 Therefore, h = u 2g u 12 For first ball, h1 = 2g u 22 and for second ball, h2= 2g u 12 2g 2 h1 u1 Thus h = u 2 = 2 or h 1 : h 2 = u 21 : u 22 2g u2 ANSWERS 131 C hapter 9 _lqucpq Multiple Choice Questions