Class 11 Physics · 25 questions · 0 with answers
Among the four graphs (Fig. 3.1), there is only one graph for which average velocity over the time intervel (0, T ) can vanish for a suitably chosen T. Which one is it?
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A lift is coming from 8 th floor and is just about to reach
th floor. T aking gr ound floor as origin and positive direction upwards for all quantities, which one of the following is correct?
The displacement of a particle is given by x = (t – 2)2 where x is in metres and t in seconds. The distance covered by the particle in first 4 seconds is
At a metro station, a girl walks up a stationary escalator in time t1. If she remains stationary on the escalator, then the escalator take Motion in a Straight Line her up in time t2. The time taken by her to walk up on the moving escalator will be
The variation of quantity A with quantity B, plotted in Fig. 3.2 describes the motion of a particle in a straight line.
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A graph of x versus t is shown in Fig. 3.3. Choose correct alternatives from below. B
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For the one-dimensional motion, described by x = t–sint
A spring with one end attached to a mass and the other to a rigid support is stretched and released.
A ball is bouncing elastically with a speed 1 m/s between walls of a railway compartment of size 10 m in a direction perpendicular to walls. The train is moving at a constant velocity of 10 m/s parallel to the direction of motion of the ball. As seen from the ground,
Refer to the graphs in Fig 3.1. Match the following. Graph Characteristic (a)
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A uniformly moving cricket ball is turned back by hitting it with a bat for a very short time interval. Show the variation of its acceleration with time. (Take acceleration in the backward direction as positive).
Give examples of a one-dimensional motion where
Give example of a motion where x > 0, v < 0, a > 0 at a particular instant.
An object falling through a fluid is observed to have acceleration given by a = g – bv where g = gravitational acceleration and b is constant. After a long time of release, it is observed to fall with constant speed. What must be the value of constant speed? Motion in a Straight Line
A ball is dropped and its displacement vs time graph is as shown Fig. 3.4 (displacement x is from ground and all quantities are +ve upwards).
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A particle executes the motion described by x (t ) = x o (1 − e −γ t ) ; t ≥ 0 , x0 > 0.
A bird is tossing (flying to and fro) between two cars moving towards each other on a straight road. One car has a speed of 18 m/h while the other has the speed of 27km/h. The bird starts moving from first car towards the other and is moving with the speed of 36km/h and when the two cars were separted by 36 km. What is the total distance covered by the bird? What is the total displacement of the bird?
A man runs across the roof-top of a tall building and jumps horizontally with the hope of landing on the roof of the next building which is of a lower height than the first. If his speed is 9 m/s, the (horizontal) distance between the two buildings is 10 m and the height difference is 9 m, will he be able to land on the next building ? (take g = 10 m/s2)
A ball is dropped from a building of height 45 m. Simultaneously another ball is thrown up with a speed vo 40 m/s. Calculate the relative speed of the balls as a function of time.
The velocity-displacement graph of a particle is shown in Fig. 3.5.
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It is a common observation that rain clouds can be at about a kilometre altitude above the ground.
A motor car moving at a speed of 72km/h can not come to a stop in less than 3.0 s while for a truck this time interval is 5.0 s. On a higway the car is behind the truck both moving at 72km/h. The truck gives a signal that it is going to stop at emergency. At what distance the car should be from the truck so that it does not bump onto (collide with) the truck. Human response time is 0.5s. (Comment : This is to illustrate why vehicles carry the message on the rear side. “Keep safe Distance”)
A monkey climbs up a slippery pole for 3 seconds and subsequently slips for 3 seconds. Its velocity at time t is given by v(t) = 2t (3-t); 0< t < 3 and v (t)=–(t–3)(6–t) for 3 < t < 6 s in m/s. It repeats this cycle till it reaches the height of 20 m.
A man is standing on top of a building 100 m high. He throws two balls vertically, one at t = 0 and other after a time interval (less than 2 seconds). The later ball is thrown at a velocity of half the first. The vertical gap between first and second ball is +15 m at t = 2 s. The gap is found to remain constant. Calculate the velocity with which the balls were thrown and the exact time interval between their throw.