Q3.25Multiple choice
A monkey climbs up a slippery pole for 3 seconds and subsequently slips for 3 seconds. Its velocity at time t is given by v(t) = 2t (3-t); 0< t < 3 and v (t)=–(t–3)(6–t) for 3 < t < 6 s in m/s. It repeats this cycle till it reaches the height of 20 m.
- (a)At what time is its velocity maximum?
- (b)At what time is its average velocity maximum?
- (c)At what time is its acceleration maximum in magnitude?
- (d)How many cycles (counting fractions) are required to reach the top?