Q51Short answer
P4O6 reacts with water according to equation P4O6 + 6H2O → 4H3PO3. Calculate the volume of 0.1 M NaOH solution required to neutralise the acid formed by dissolving 1.1 g of P4O6 in H2O.
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P4O6 + 6H2O → 4H3PO3 H3PO3 + 2NaOH → Na2 HPO3 + 2H2O] × 4 (Neutralisation reaction) P4O6 + 8NaOH → 4Na2 HPO4 + 2H2O 1 mol 8 mol Product formed by 1 mol of P4O6 is neutralised by 8 mols of NaOH 1.1 1.1 ∴ Product formed by mol of P4O6 will be neutralised by × 8 mol 220 220 of NaOH Molarity of NaOH solution is 0.1M ⇒ 0.1 mol NaOH is present in 1 L solution 1.1 1.1 × 8 88 4 ∴ × 8 mol NaOH is present in L = L = L = 0.4 L = 220 220 × 0.1 220 10 400 mL of NaOH solution.