Q52Short answer
White phosphorus reacts with chlorine and the product hydrolyses in the presence of water. Calculate the mass of HCl obtained by the hydrolysis of the product formed by the reaction of 62 g of white phosphorus with chlorine in the presence of water.
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P4 + 6Cl2 → 4PCl3 PCl3 + 3H2O → H3PO3 + 3HCl] × 4 P4 + 6Cl2 + 12H2O → 4H3PO3 + 12HCl 1 mol of white phosphorus produces 12 mol of HCl 62 1 62g of white phosphorus has been taken which is equivalent to = mol. 124 2 Therefore 6 mol HCl will be formed. Mass of 6 mol HCl = 6 × 36.5 = 219.0 g HCl