Q2Short answer
x 3x 2 1 =1– + – 2 3 x +1 1 x3 = 1 – x + x2 – = . x +1 x +1 x 2 x3 x3 Thus x – + – log x + 1 + C ∫ = dx 2 3 x +1 1+ x
x 3x 2 1 =1– + – 2 3 x +1 1 x3 = 1 – x + x2 – = . x +1 x +1 x 2 x3 x3 Thus x – + – log x + 1 + C ∫ = dx 2 3 x +1 1+ x