Q4Short answer
2 t A B Consider = + t + 3t + 2 t + 1 t + 2 Comparing coefficient, we get A = –1, B = 2. 1 dt dt 2∫ –∫ t + 1 Then I= 2 t+2 2log t + 2 − log t +1 2 = x2 + 2 = log +C x2 + 1
2 t A B Consider = + t + 3t + 2 t + 1 t + 2 Comparing coefficient, we get A = –1, B = 2. 1 dt dt 2∫ –∫ t + 1 Then I= 2 t+2 2log t + 2 − log t +1 2 = x2 + 2 = log +C x2 + 1