Chapter 10 – Circles

Class 9 Mathematics · 55 questions · 22 with answers

Solved examples

Ex. 1Multiple choice

In Fig. 10.1, two congruent circles have centres O and O′. Arc AXB subtends an angle of 75º at the centre O and arc A′ Y B′ subtends an angle of 25º at the centre O′. Then the ratio of arcs A X B and A′ Y B′ is: Fig. 10.1

  • (A)2 : 1
  • (B)1 : 2
  • (C)3 : 1
  • (D)1 : 3
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Solution : Answer (C)

Ex. 2Multiple choice

In Fig. 10.2, AB and CD are two equal chords of a circle with centre O. OP and OQ are perpendiculars on chords AB and CD, respectively. If ∠POQ = 150º, then ∠APQ is equal to

  • (A)30º
  • (B)75º
  • (C)15º
  • (D)60º
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Solution : Answer (B) Fig. 10.2 CIRCLES 99

Ex. 1Short answerExercise 10.1

The angles subtended by a chord at any two points of a circle are equal.

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Solution : False. If two points lie in the same segment (major or minor) only, then the angles will be equal otherwise they are not equal. Sample Questions 2 : Two chords of a circle of lengths 10 cm and 8 cm are at the distances 8.0 cm and 3.5 cm, respectively from the centre. Solution: False. As the larger chord is at smaller distance from the centre.

Ex. 1Short answerExercise 10.2

In Fig. 10.11, AOC is a diameter of the circle and arc AXB = arc BYC. Find ∠BOC.

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Solution : As arc AXB = arc BYC, ∠AOB = ∠BOC Also ∠AOB + ∠BOC = 180º

Ex. 2Short answerExercise 10.2

In Fig. 10.12, ∠ABC = 45º, prove that OA ⊥ OC.

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Solution : ∠ABC = ∠AOC i.e., ∠AOC = 2∠ABC = 2 × 45º = 90º Fig. 10.12 or OA ⊥ OC

Ex. 1Short answerExercise 10.3

Prove that two circles cannot intersect at more than two points.

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Solution : Let there be two circles which intersect at three points say at A, B and C. Clearly, A, B and C are not collinear. We know that through three non-collinear points A, B and C one and only one circle can pass. Therefore, there cannot be two circles passing through A, B and C. In other words, the two circles cannot intersect at more than two points.

Ex. 2Short answerExercise 10.3

Prove that among all the chords of a circle passing through a given point inside the circle that one is smallest which is perpendicular to the diameter passing through the point.

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Solution : Let P be the given point inside a circle with centre O. Draw the chord AB which is perpendicular to the diameter XY through P. Let CD be any other chord through P. Draw ON perpendicular to CD from O. Then ∆ONP is a right triangle (Fig.10.17). Therefore, its hypotenuse OP is larger than ON. We know that the chord nearer to the centre is larger than the chord which is farther to the centre. Therefore, CD > AB. In other words, AB is the smallest of all chords passing through P. Fig. 10.17

Questions

Q1Multiple choiceExercise 10.1

AD is a diameter of a circle and AB is a chord. If AD = 34 cm, AB = 30 cm, the distance of AB from the centre of the circle is :

  • (A)17 cm
  • (B)15 cm
  • (C)4 cm
  • (D)8 cm
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(D) 8 cm

Q2Multiple choiceExercise 10.1

In Fig. 10.3, if OA = 5 cm, AB = 8 cm and OD is perpendicular to AB, then CD is equal to:

This question refers to a figure in the original PDF.

  • (A)2 cm
  • (B)3 cm
  • (C)4 cm
  • (D)5 cm
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(A) 2 cm

Q3Multiple choiceExercise 10.1

If AB = 12 cm, BC = 16 cm and AB is perpendicular to BC, then the radius of the circle passing through the points A, B and C is :

  • (A)6 cm
  • (B)8 cm
  • (C)10 cm
  • (D)12 cm
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(C) 10 cm

Q4Multiple choiceExercise 10.1

In Fig.10.4, if ∠ABC = 20º, then ∠AOC is equal to: Fig. 10.3

This question refers to a figure in the original PDF.

  • (A)20º
  • (B)40º
  • (C)60º
  • (D)10º Fig. 10.4
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(B) 40º

Q5Multiple choiceExercise 10.1

In Fig.10.5, if AOB is a diameter of the circle and AC = BC, then ∠CAB is equal to:

This question refers to a figure in the original PDF.

  • (A)30º
  • (B)60º
  • (C)90º
  • (D)45º Fig. 10.5
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(D) 45º Fig. 10.5

Q6Multiple choiceExercise 10.1

In Fig. 10.6, if ∠OAB = 40º, then ∠ACB is equal to :

This question refers to a figure in the original PDF.

  • (A)50º
  • (B)40º
  • (C)60º
  • (D)70° Fig. 10.6
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(A) 50º

Q7Multiple choiceExercise 10.1

In Fig. 10.7, if ∠DAB = 60º, ∠ABD = 50º, then ∠ACB is equal to:

This question refers to a figure in the original PDF.

  • (A)60º
  • (B)50º
  • (C)70º
  • (D)80º Fig. 10.7
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(C) 70º

Q8Multiple choiceExercise 10.1

ABCD is a cyclic quadrilateral such that AB is a diameter of the circle circumscribing it and ∠ADC = 140º, then ∠BAC is equal to:

  • (A)80º
  • (B)50º
  • (C)40º
  • (D)30º
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(B) 50º

Q9Multiple choiceExercise 10.1

In Fig. 10.8, BC is a diameter of the circle and ∠BAO = 60º. Then ∠ADC is equal to :

This question refers to a figure in the original PDF.

  • (A)30º
  • (B)45º
  • (C)60º
  • (D)120º Fig. 10.8 CIRCLES 101
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(C) 60º

Q10Multiple choiceExercise 10.1

In Fig. 10.9, ∠AOB = 90º and ∠ABC = 30º, then ∠CAO is equal to:

This question refers to a figure in the original PDF.

  • (A)30º
  • (B)45º
  • (C)90º
  • (D)60º Fig. 10.9
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(D) 60º Fig. 10.9

Q1Short answerExercise 10.2

Two chords AB and CD of a circle are each at distances 4 cm from the centre. Then AB = CD.

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True. Because the distances from the centre of two chords are equal.

Q2Short answerExercise 10.2

Two chords AB and AC of a circle with centre O are on the opposite sides of OA. Then ∠OAB = ∠OAC .

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False. The angles will be equal only if AB = AC.

Q3Short answerExercise 10.2

Two congruent circles with centres O and O′ intersect at two points A and B. Then ∠AOB = ∠AO′B.

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True. Because equal chords of congruent circles subtend equal angles at the respective centres.

Q4Short answerExercise 10.2

Through three collinear points a circle can be drawn.

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False. Because a circle through two points cannot pass through a point which is collinear to these two points.

Q5Short answerExercise 10.2

A circle of radius 3 cm can be drawn through two points A, B such that AB = 6 cm.

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True. Because AB will be the diameter.

Q6Short answerExercise 10.2

If AOB is a diameter of a circle and C is a point on the circle, then AC2 + BC2 = AB 2.

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True. As ∠C is right angle, AC2 + BC2 = AB2.

Q7Short answerExercise 10.2

ABCD is a cyclic quadrilateral such that ∠A = 90°, ∠B = 70°, ∠C = 95° and ∠D = 105°.

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False, as ∠A + ∠C = 90°+ 95° = 185° ≠ 180°.

Q8Short answerExercise 10.2

If A, B, C, D are four points such that ∠BAC = 30° and ∠BDC = 60°, then D is the centre of the circle through A, B and C.

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False, because there can be many points D such that ∠BDC = 60° and each such point cannot be the centre of the circle through A,B,C.

Q9Short answerExercise 10.2

If A, B, C and D are four points such that ∠BAC = 45° and ∠BDC = 45°, then A, B, C, D are concyclic.

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True. Angles in the same segment.

Q10Short answerExercise 10.2

In Fig. 10.10, if AOB is a diameter and ∠ADC = 120°, then ∠CAB = 30°. Fig. 10.10

This question refers to a figure in the original PDF.

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True. ∠B = 180° –120° = 60° , ∠CAB = 90° – 60° = 30°.

Q1Short answerExercise 10.2

Fig. 10.11 Therefore, ∠BOC + ∠BOC = 180º CIRCLES 103 or ∠BOC = × 180º = 120º

This question refers to a figure in the original PDF.

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True. Because the distances from the centre of two chords are equal.

Q1Short answerExercise 10.3

If arcs AXB and CYD of a circle are congruent, find the ratio of AB and CD.

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1:1 9. 60° 14. 30° 15. 100° 16. 50° 17. 40° 19. 278 20. ∠BOC = 66°, ∠AOC = 54°

Q2Short answerExercise 10.3

If the perpendicular bisector of a chord AB of a circle PXAQBY intersects the circle at P and Q, prove that arc PXA ≅ Arc PYB.

Q3Short answerExercise 10.3

A, B and C are three points on a circle. Prove that the perpendicular bisectors of AB, BC and CA are concurrent.

Q4Short answerExercise 10.3

AB and AC are two equal chords of a circle. Prove that the bisector of the angle BAC passes through the centre of the circle.

Q5Short answerExercise 10.3

If a line segment joining mid-points of two chords of a circle passes through the centre of the circle, prove that the two chords are parallel.

Q6Short answerExercise 10.3

ABCD is such a quadrilateral that A is the centre of the circle passing through B, C and D. Prove that ∠CBD + ∠CDB = ∠BAD

Q7Short answerExercise 10.3

O is the circumcentre of the triangle ABC and D is the mid-point of the base BC. Prove that ∠BOD = ∠A.

Q8Short answerExercise 10.3

On a common hypotenuse AB, two right triangles ACB and ADB are situated on opposite sides. Prove that ∠BAC = ∠BDC.

Q9Short answerExercise 10.3

Two chords AB and AC of a circle subtends angles equal to 90º and 150º, respectively at the centre. Find ∠BAC, if AB and AC lie on the opposite sides of the centre.

Q10Short answerExercise 10.3

If BM and CN are the perpendiculars drawn on the sides AC and AB of the triangle ABC, prove that the points B, C, M and N are concyclic.

Q11Short answerExercise 10.3

If a line is drawn parallel to the base of an isosceles triangle to intersect its equal sides, prove that the quadrilateral so formed is cyclic.

Q12Short answerExercise 10.3

If a pair of opposite sides of a cyclic quadrilateral are equal, prove that its diagonals are also equal.

Q13Short answerExercise 10.3

The circumcentre of the triangle ABC is O. Prove that ∠OBC + ∠BAC = 90º.

Q14Short answerExercise 10.3

A chord of a circle is equal to its radius. Find the angle subtended by this chord at a point in major segment.

Q15Short answerExercise 10.3

In Fig.10.13, ∠ADC = 130° and chord BC = chord BE. Find ∠CBE. Fig. 10.13 Fig. 10.14

This question refers to a figure in the original PDF.

Q16Short answerExercise 10.3

In Fig.10.14, ∠ACB = 40º. Find ∠OAB.

This question refers to a figure in the original PDF.

Q17Short answerExercise 10.3

A quadrilateral ABCD is inscribed in a circle such that AB is a diameter and ∠ADC = 130º. Find ∠BAC.

Q18Short answerExercise 10.3

Two circles with centres O and O′ intersect at two points A and B. A line PQ is drawn parallel to OO′ through A(or B) intersecting the circles at P and Q. Prove that PQ = 2 OO′.

Q19Short answerExercise 10.3

In Fig.10.15, AOB is a diameter of the circle and C, D, E are any three points on the semi-circle. Find the value of ∠ACD + ∠BED. Fig. 10.15 CIRCLES 105

This question refers to a figure in the original PDF.

Q20Short answerExercise 10.3

In Fig. 10.16, ∠OAB = 30º and ∠OCB = 57º. Find ∠BOC and ∠AOC. Fig. 10.16

This question refers to a figure in the original PDF.

Q1Short answerExercise 10.4

If two equal chords of a circle intersect, prove that the parts of one chord are separately equal to the parts of the other chord.

Q2Short answerExercise 10.4

If non-parallel sides of a trapezium are equal, prove that it is cyclic.

Q3Short answerExercise 10.4

If P, Q and R are the mid-points of the sides BC, CA and AB of a triangle and AD is the perpendicular from A on BC, prove that P, Q, R and D are concyclic.

Q4Short answerExercise 10.4

ABCD is a parallelogram. A circle through A, B is so drawn that it intersects AD at P and BC at Q. Prove that P, Q, C and D are concyclic.

Q5Short answerExercise 10.4

Prove that angle bisector of any angle of a triangle and perpendicular bisector of the opposite side if intersect, they will intersect on the circumcircle of the triangle.

Q6Short answerExercise 10.4

If two chords AB and CD of a circle AYDZBWCX intersect at right angles (see Fig.10.18), prove that arc CXA + arc DZB = arc AYD + arc BWC = semi- circle. Fig. 10.18

This question refers to a figure in the original PDF.

Q7Short answerExercise 10.4

If ABC is an equilateral triangle inscribed in a circle and P be any point on the minor arc BC which does not coincide with B or C, prove that PA is angle bisector of ∠BPC.

Q8Short answerExercise 10.4

In Fig. 10.19, AB and CD are two chords of a circle intersecting each other at point E. Prove that ∠AEC = (Angle subtended by arc CXA at centre + angle subtended by arc DYB at the centre). Fig. 10.19 CIRCLES 107

This question refers to a figure in the original PDF.

Q9Short answerExercise 10.4

If bisectors of opposite angles of a cyclic quadrilateral ABCD intersect the circle, circumscribing it at the points P and Q, prove that PQ is a diameter of the circle.

Q10Short answerExercise 10.4

A circle has radius 2 cm. It is divided into two segments by a chord of length 2 cm. Prove that the angle subtended by the chord at a point in major segment is 45º.

Q11Short answerExercise 10.4

Two equal chords AB and CD of a circle when produced intersect at a point P. Prove that PB = PD.

Q12Short answerExercise 10.4

AB and AC are two chords of a circle of radius r such that AB = 2AC. If p and q are the distances of AB and AC from the centre, prove that 4q2 = p2 + 3r2.

Q13Short answerExercise 10.4

In Fig. 10.20,O is the centre of the circle, ∠BCO = 30°. Find x and y. Fig. 10.20

This question refers to a figure in the original PDF.

Q14Short answerExercise 10.4

In Fig. 10.21, O is the centre of the circle, BD = OD and CD ⊥ AB. Find ∠CAB. Fig. 10.21

This question refers to a figure in the original PDF.