Q1Short answerExercise 10.2
Fig. 10.11 Therefore, ∠BOC + ∠BOC = 180º CIRCLES 103 or ∠BOC = × 180º = 120º
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True. Because the distances from the centre of two chords are equal.
Fig. 10.11 Therefore, ∠BOC + ∠BOC = 180º CIRCLES 103 or ∠BOC = × 180º = 120º
This question refers to a figure in the original PDF.
True. Because the distances from the centre of two chords are equal.